981. Time Based Key-Value Store 時間戳的題目
981. Time Based Key-Value Store 時間戳的題目
Design a time-based key-value data structure that can store multiple values for the same key at different time stamps and retrieve the key's value at a certain timestamp.
Implement the TimeMap class:
TimeMap()Initializes the object of the data structure.void set(String key, String value, int timestamp)Stores the keykeywith the valuevalueat the given timetimestamp.String get(String key, int timestamp)Returns a value such thatsetwas called previously, withtimestamp_prev <= timestamp. If there are multiple such values, it returns the value associated with the largesttimestamp_prev. If there are no values, it returns"".
Example 1:
Input ["TimeMap", "set", "get", "get", "set", "get", "get"] [[], ["foo", "bar", 1], ["foo", 1], ["foo", 3], ["foo", "bar2", 4], ["foo", 4], ["foo", 5]] Output [null, null, "bar", "bar", null, "bar2", "bar2"] Explanation TimeMap timeMap = new TimeMap(); timeMap.set("foo", "bar", 1); // store the key "foo" and value "bar" along with timestamp = 1. timeMap.get("foo", 1); // return "bar" timeMap.get("foo", 3); // return "bar", since there is no value corresponding to foo at timestamp 3 and timestamp 2, then the only value is at timestamp 1 is "bar". timeMap.set("foo", "bar2", 4); // store the key "foo" and value "bar2" along with timestamp = 4. timeMap.get("foo", 4); // return "bar2" timeMap.get("foo", 5); // return "bar2"
Constraints:
1 <= key.length, value.length <= 100keyandvalueconsist of lowercase English letters and digits.1 <= timestamp <= 107- All the timestamps
timestampofsetare strictly increasing. - At most
2 * 105calls will be made tosetandget.
解法:
我的解法 對於每一個[key]先建立一個dictionary,dictionary map timestamp to value
意思就是字典中包含的字典
不只如此,針對每一個key,創造另一個list ,含有所有時間形成的list
之後就可以用這個list 來做binary search,因為題目特別提到 時間戳只會遞增
基本上就是 binary search on tuples。
使用bisect right python套件即可
歡迎參考底下的code
class TimeMap: def __init__(self): self.d= defaultdict(dict) self.key=defaultdict(list) def set(self, key: str, value: str, timestamp: int) -> None: self.d[key][timestamp]=value self.key[key].append(timestamp) def get(self, key: str, timestamp: int) -> str: if key not in self.d: return "" i=bisect.bisect_right(self.key[key],timestamp) if i!=0: return self.d[key][self.key[key][i-1]] else: return ""
留言
張貼留言